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In the figure, the perimeter of trapezoid ABCD is 58. What is the perimeter of rectangle FBCE?

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The perimeter of trapezoid ABCD is 58

→ 2 x 6 + 2 x 13 + AB + CD = 58

AB +CD = 20

Since AB = CD, AB = CD = 10

BF = CE = $BF = CE = \sqrt{10^{2}-6^{2}} = 8$

BC=13 FC= 13 BF=8 CE=8

13+13+8+8=42